The greatest number which on dividing 1659
WebThe greatest number which on dividing 1659 and 2036 leaves remainders 8 and 4, respectively is A 124 B 129 C 127 D 305 Easy Solution Verified by Toppr Correct option is C) Step -1: Substracting the Remainder from given number Remainders are 8 & 4. Substract … WebThe greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is: = H.C.F. of 1651 and 2032 = 127. Consider a two-digit number. The difference between the number and the number we get when its digits are reversed is 27. If the sum of the digits in the given number is 9, find the HCF of the number and the number ...
The greatest number which on dividing 1659
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Web7 Dec 2024 · The required number is "127". Step-by-step explanation: We have, Required number = H.C.F. of (1659 - 8) and (2036 - 4) = 1651 and 2032. ∴ Required number = H.C.F. … WebThe greatest number which on dividing 1659 and 2036 leaves remainders 8 and 4 nespertively is 124 6.129 6 of 305.
WebRequired number= H.C.F. of (1657−6) and (2037−5)= H.C.F. of 1651 and 20321657= 13×1272037= 2×2×2×2×127Common −127Required number = 127. Web11 Apr 2024 · The greatest number which divides each of the two or more numbers is called HCF or Highest Common Factor. Calculations: Required number = H.C.F. of (1657 - 6) and (2037 - 5) H.C.F. of 1651 and 2032. 1651 = 13 × 127 . 2032 = …
WebThe greatest number which divides each of the two or more numbers is called HCF or Highest Common Factor. ∴ The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is 127. Remainders are 8 and 4 1659-8=1651 2036-4=2032 HCF of 1651 and 2032 is 127 =>the greatest no. is 127. WebThe HCF of 1651 and 2032 is the greatest integer that can divide both numbers evenly, and that number is 127. HCF stands for Highest Common Factor. It is also known as GCF, Greatest Common Factor or GCD, Greatest Common Divisor. For a given set of numbers, there would be multiple common factors, and the highest among the common factors is …
WebOur numbers here are 91−43=48,183−91=92,183−43=140 So we have the set of numbers {48,92,140} and we want to know the biggest number that divides all these numbers. So, 48=2×2×2×3 92=2×2×23 140=2×2×5×7 The greatest common divisor of {48,92,140} is 4. So, answer is 4. Was this answer helpful? 0 0 Similar questions
Web5 Jan 2024 · "The greatest number which on dividing 1659 and 2036 leaves remainder 8 and 4" Solution of the above Question: 127. Step-by-step explanation: getting remainder 8 … scottish honey berry growersWeb27 Oct 2024 · 0 = Q × (any nonzero whole number) From our knowledge of multiplication, we can understand that if the product of two whole numbers is zero, then one or both of the whole numbers must be zero. Since any nonzero whole number is certainly not zero, Q must represent zero. Then, 0 any nonzero whole number = 0. Therefore zero divided any … preschool australia absWeb22 Mar 2024 · Solution For The greatest number which on dividing 1659 and 2036 leaves remainder 8 and 4 respeciting is. preschool australiaWeb2 Jan 2024 · Euclidean Algorithm for Greatest Common Divisor (GCD) The Euclidean Algorithm finds the GCD of 2 numbers. You will better understand this Algorithm by seeing it in action. Assuming you want to calculate the GCD of 1220 and 516, let's apply the Euclidean Algorithm. Pseudo Code of the Algorithm: Step 1: Let a, b be the two numbers Step 2: a … preschool auroraWeb5 Jan 2024 · So, The greatest number which on dividing 1659 and 2036 leaves remainder 8 and 4 is 127. Advertisement Advertisement New questions in Math. A solid has volume 6 cubic units and surface area 22 square units. The solid is dilated, and the image has volume 384 cubic units. Answer the followin … scottish honeyberryWebThere are multiple ways to find the greatest common factor of given integers. One of these involves computing the prime factorizations of each integer, determining which factors they have in common, and multiplying these factors to find the GCD. Refer to the example below. EX: GCF (16, 88, 104) 16 = 2 × 2 × 2 × 2. 88 = 2 × 2 × 2 × 11. scottish honey beeWeb13 Dec 2024 · Original numbers = 1659 and 2036 • Subtract the remainders from the numbers, we get. 1659-8 = 1651. 2036-4 = 2032. Now, We need to find the H.C.F of these … preschool audio books free