WebJul 1, 2024 · Click here 👆 to get an answer to your question ️ A force of (10i -3j+6k) N acts on a body of mass 100gand displaces it from (6i+5j– 3k) m to (10i - 2j+ 7k)m.T… niranjandk03 niranjandk03 01.07.2024 WebDec 5, 2024 · A force of (10i-3j+6k) N acts on a body of 5 kg and displaces it from A (6i+5j-3k)m to B (10i-2j+ 7k)m. The work done is (a) zero (c) 100J (b) 121j (d) 221j Advertisement shivam1610 is waiting for your help. Add your answer and earn points. Answer No one rated this answer yet — why not be the first? 😎 zairafatima23
Solved 3. Given A= -3i + 5j, and B = 10i +2j. Calculate in
WebThe position vectors of points A, B and C relative to the origin O are 2i + 3j, 10i + 2j and λ (-i + 5j) respectively. (a) Obtain an expression in terms of λ for (i) AC (ii) AC (b) Given that AB = … WebIf the vectors AB =−3^i +4^k and AC=5^i−2^j +4^k are the sides of a triangle ABC. Then the length of the median through A is. Q. The vectors −→ AB=3^i +4^k and −→ AC=5^i −2^j … commerce township backflow testing
A force of (10i -3j+6k) N acts on a body of mass 100g
Web(2,−1,4). We can then form the vector AB. Now what is the magnitude of this vector, and what are its direction cosines? We can answer these questions by writing the two position vectors OA and OB in terms of the unit vectors ˆi, ˆj and ˆk. We obtain OA = ˆi+2kˆ OB = 2ˆi−ˆj+4ˆk. A B O So AB = AO +OB = OB −OA = (2ˆi−ˆj+4ˆk)− ... WebOct 19, 2024 · asked Oct 19, 2024 in Vector algebra by Abhinav03 (64.8k points) Two adjacent sides of a parallelogram ABCD are given by vector AB = 2i + 10j + 11k and vector AD = - i + 2j + 2k. The side AD is rotated by an acute angle α in the plane of the parallelogram so that AD becomes AD’. WebThis problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer Question: 3. Given A= -3i + 5j, and B = 10i +2j. … commerce township ballot